Speed of sound

echo_delay <- read.delim("echo_delay.txt")

We will analyze the results of the sound speed experiment, contained in the file echo_delay.txt. There are 527 samples and 4 variables. The following table shows the first and last four rows

kable(echo_delay[c(1:4, nrow(echo_delay)-3:0),])

The column id is the sample serial number. Some cases have been omitted, as described in the experiment protocol document. The column elapsed represent how many seconds passed since the start of the experiment until the sample was taken. It is used for data pre-processing and quality control, but it is not needed for the current analysis. In this case, the most important variables are delay and distance. The variable delay⊕delay: units 10^-6s, resolution ±0.5

is the number of microseconds that passed between sending the ultrasonic signal and receiving the echo. The resolution is one microsecond. There is some variability that shall be treated statistically.

The variable distance⊕distance: units 10^-3m, resolution ±0.5

is the distance between the sensor border and the wall where the echo bounces. The total traveled distance is twice this value. It is measured in millimeters, with a margin of error of 1mm. There may be an unknown offset between the real position of the sensor and the place used as reference for distance.

Their relationship is, by definition, given by \[speed\cdot delay =2\cdot(\mathit{distance}+\mathit{offset})\] Remember that the sound travels distance twice. We can rewrite this formula⊕In principle we can also use the model \[{distance}=2\cdot speed\cdot delay+\mathit{offset}\] but it is harder to analyze, since delay is not the variable that we control. Instead we control distance.

in a more convenient way as \[\mathit{delay} =\frac{2}{\mathit{speed}}\cdot\mathit{distance}+\frac{2\cdot \mathit{offset}}{speed}\] This formula has the shape of a linear model \[\mathit{delay} =\beta_1\cdot\mathit{distance}+\beta_0\]

Fitting the model will give us two parameters: an intercept \(\beta_0\) that will correspond to the 2 offset/speed, and a factor for distance that will correspond to 2/speed.

For some distances we have several samples, while in others we have only a few. We have to take them in consideration when we fit the linear model, since the cases with more samples will have more weight than the cases with fewer samples.

plot(delay~id, data=echo_delay,
    main="Delay [ms] for each sample")

We have to count the number of samples in each case

num_samples <- table(echo_delay$distance)
num_samples

 12  20  30  40  50  60  70  80  90 100 110 120 130 140 150 160 170 180 
 67  25  25  23  24  42  19  11  27  31  26  20  43  27  29  25  25  38 

Now we can fit a linear model to this data, including weights proportional to the inverse of the number of samples per case.⊕New concept: Weighted linear models.

This way the cases with more sample are compensated, and each distance has the same relative influence in the model. We build a linear model, store it in the variable model, and plot it with the following command

model <- lm(delay~distance, data=echo_delay, 
                weights = 1/num_samples[as.character(distance)])
plot(delay~distance, data=echo_delay)
abline(model)

Now we can see the details of model using this command

summary(model)

Call:
lm(formula = delay ~ distance, data = echo_delay, weights = 1/num_samples[as.character(distance)])

Weighted Residuals:
   Min     1Q Median     3Q    Max 
 -8.79  -3.73   1.04   3.17   9.82 

Coefficients:
            Estimate Std. Error t value Pr(>|t|)    
(Intercept) -17.8287     2.0721    -8.6   <2e-16 ***
distance      6.0881     0.0191   318.1   <2e-16 ***
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

Residual standard error: 4.2 on 525 degrees of freedom
Multiple R-squared:  0.995, Adjusted R-squared:  0.995 
F-statistic: 1.01e+05 on 1 and 525 DF,  p-value: <2e-16

There are several values in this result. For now we care only about the two first columns in the table “Coefficients”. There are two rows, one for each parameter. The column “Estimate” represents the best estimation for each parameter, and the column “Std. Error” represents the standard error of the same parameter. That is enough for us to determine confidence intervals for the parameters. In R this is easy, we just use

confint(model, level=0.99)

             0.5 % 99.5 %
(Intercept) -23.19 -12.47
distance      6.04   6.14

Your challenge is:

• Replicate this linear model from the same data
• You can use R, Excel or any tool of your preference.
• What is the meaning of each coefficient?
• What are the units of each coefficient?
• Calculate a 95% confidence interval for the speed of sound.
• Does this interval match your background information?

Acceleration of gravity

For the “Computing in Molecular Biology” course I try to use realistic data. It is difficult to do biological experiments during classes, since they require a lot of time. That is why I prefer to do physics experiments. In 2018 we did one of those experiments, described in its own article.

I made a web page with a timer and a distance scale, which was projected on the wall. The students used their cell phones to record a video of a falling ball. My version of the video is in YouTube. The key part of the video is summarized in the following picture.

With some tools that are explained on the original post, we got a table describing the distance travelled by the ball on each time. The distance column represents the vertical position in meters, and time is measured in seconds. There is some uncertainty on the distance, that I guess can be near 5cm. The time is more precise, as described in the experiment page. Our data looks like this:

freefall <- read.table("freefall_from_movie.txt",
                        header=TRUE)
plot(distance ~ time, data=freefall,
    main="Experimental data. Distance [m] v/s time [s]")

Since the ball distance follows a parabola, we would like to model it with a formula like \[\mathit{distance}=\beta_2\cdot\mathit{time}^2+\beta_1\cdot\mathit{time}+\beta_0\] Interestingly, we can fit this quadratic formula with a linear model⊕New concept: Quadratic linear models.

. We need to add a new column, called time_sq, with the time squared. Then we fit a linear model.

freefall <- transform(freefall, time_sq=time^2)
model_fall <- lm(distance ~ time + time_sq, data=freefall)

plot(distance ~ time, data=freefall,
            main="Data and fitted quadratic model")
pred <- predict(model_fall)
lines(pred ~ time, data=freefall, col="red", lwd=2)

The fitted parameters of this model can be seen with the following commands

summary(model_fall)

Call:
lm(formula = distance ~ time + time_sq, data = freefall)

Residuals:
     Min       1Q   Median       3Q      Max 
-0.02641 -0.00795  0.00133  0.00809  0.01970 

Coefficients:
            Estimate Std. Error t value Pr(>|t|)    
(Intercept)  0.19495    0.00278   70.01  < 2e-16 ***
time         0.11290    0.02287    4.94  2.3e-06 ***
time_sq     -5.03312    0.03934 -127.94  < 2e-16 ***
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

Residual standard error: 0.011 on 133 degrees of freedom
Multiple R-squared:  0.999, Adjusted R-squared:  0.999 
F-statistic: 1.2e+05 on 2 and 133 DF,  p-value: <2e-16

confint(model_fall)

              2.5 % 97.5 %
(Intercept)  0.1894  0.200
time         0.0677  0.158
time_sq     -5.1109 -4.955

Your challenge is:

• Replicate this linear model from the same data
• You can use R, Excel or any tool of your preference.
• What is the meaning of each coefficient?
• What are the units of each coefficient?
• Calculate a 95% confidence interval for the acceleration of gravity.
• Does this interval match your background information?